2x^2-84.5=0

Solution for 2x^2-84.5=0 equation:

2x^2-84.5=0

a = 2; b = 0; c = -84.5;
Δ = b2-4ac
Δ = 02-4·2·(-84.5)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-26}{2*2}=\frac{-26}{4}
=-6+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+26}{2*2}=\frac{26}{4}
=6+1/2
$